💪schloodinger equation,
appear from Maxwell's equations
source: Erwin Rudolf Josef Alexander Schrödinger, professor miyajima
article to confirm
how to write schloodinger equation.
take long time to write ...
➀ Euler's formula e ^ i θ = cos θ + i sin θ
② from Maxwell's equations,
∇ × E = - ∂ B / ∂ t ... equation ➀
∇ × B = ε₀μ₀ ∂ E / ∂ t ... equation ②
E : Electric field - Wikipedia
B : Magnetic field - Wikipedia
∇ = ( ∂ / ∂x , ∂ / ∂y, ∂ / ∂z )
∇ × ( X, Y, Z ) = ( (∂Z / ∂y - ∂Y / ∂z ) ), ( ∂X / ∂z - ∂Z / ∂x ) , ( ∂Y / ∂x - ∂X / ∂y ) )
if we multiple ∇ from left side of equation ➀,
we can substitute ∇ × B in right side of equation ➀
with ε₀μ₀ ∂ E / ∂ t
∇ × ∇ × B = ∇ × ( ε₀μ₀ ∂ E / ∂ t )
= ε₀ μ₀ ∂ ( ∇ × E ) / ∂ t
= ε₀μ₀ ∂ ² B / ∂ t ²
<=> ∇² B = ε₀μ₀ ∂ ² B / ∂ t ²
if we multiple ∇ from left side of equation ②,
we can substitute ∇ × E in right side of equation ②
with ( - ∂ B / ∂ t ) ...
∇ × ( ∇ × E ) = ∇ × ( - ∂ B / ∂ t )
= - ∂ ( ∇ × B ) / ∂ t
= ε₀μ₀ ∂ ² E / ∂ t ²
<=> ∇² E = ε₀μ₀ ∂ ² E / ∂ t ²
if dimention of left part & right part is different,
equation wont stands.
dimention of left equation ( ... differentiate 2 time, with ∇ )
= dimention of right equation ( ... differentiate 2 time, with t )
so dimention of (x, y, z), t
not change with differentiate,
but constant value appear from differentiation.
so, we found next equation:
∇ × ( ∇ × E ) = ∇² E = constant ・ E
∇ × ∇ × B = ∇² B = constant ・ B
( if E, differentiate twice, E appears )
( if B, differentiate twice, B appears )
③ what is function of E ?
1⃣ sin i θ
2⃣ cos i θ
3⃣ e ^ i θ
differentiate twice with θ,
original function appears.
=> satisfy condition of E and B.
④ if light wave move to x axis,
& if light wave vibrate to y axis,
f ( x, y ) = ( v t , e^ i ( kx - ωt ) )
is one of the function,
that can be solution of Maxwell's equations
extra:
how to get 💪schloodinger equation Ψ ?
Ψ = e^ i ( k x - ω t ) = e^ i ( ( p x - Et ) / ħ )
➀ k = 2π / λ = 2 π p / h = p / ħ
=> kx = ( p / ħ ) x
② ω = 2π ν = 2 π E / h = E / ħ
=> ω x = ( E / ħ ) x
with
2 π = k λ ( 2π = Wave number x light wavelength )
2π ... when wave function = sin θ, cos θ,
when wave return to original state,
θ = 2π
p = h / λ ( momentum = Planck constant / light wavelength )
E = h ν ( energy = Planck constant x light frequency )
if Ψ = e^ i ( ( p x - Et ) / ħ ),
∂ ² Ψ / ∂ x ² = ( p² ( - 1 / ħ ² ) ) Ψ ... 4⃣
∂ Ψ / ∂ t = ( E ( - i / ħ ) ) Ψ ... 5⃣
usually, E = p ² / 2m ... 6⃣
then
4⃣ & 5⃣ & 6⃣ =>
( i ħ ) ∂ Ψ / ∂ t = ( ħ² / 2m ) ∂ ² Ψ / ∂ x ² ... 💪schloodinger equation
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